- #1

jianghan

- 25

- 0

I think i have a rough idea of how to do this question,but somehow my answers doesn't agree with the answer key!

i think as 2as=v

^{2},energy of electron after going down 1m should be (1/3200)*50GeV,which is 2.5x10

^{-12}joules,using eqn for relativistic kinetic energy

KE=MC

^{2}/√1-V

^{2}/C

^{2},V works out to be 0.99946c

up to here my result agrees with the answer key

then i calculated relativistic momentum of electron to be 8.31x10

^{-21}kgm/s using MV/√1-V

^{2}/C

^{2}.

using eqn r=MV/Bq,sub in r=280m,i get B=1.86x10

^{-4}Tesla while the answer is 0.597T ?