A question about perturbation series inversion

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SUMMARY

The discussion focuses on the mathematical inversion of perturbation series in the context of physical quantities. It establishes that for a measure \( m \) and a bare value \( m_0 \), the series can be expressed as \( m = m_0 + f(k, m_0) + \sum_{n} u^{n} c_{n} \), where \( u = \log(\Lambda) \). The participants confirm that it is possible to invert this series to express \( \log(\Lambda) \) as a function \( g(f(k, m_0), m, m_0) \). Additionally, they explore the implications of including powers of the regulator \( \Lambda^k \) in the series expansion.

PREREQUISITES
  • Understanding of perturbation theory in physics
  • Familiarity with series expansions and convergence
  • Knowledge of logarithmic functions and their properties
  • Basic skills in mathematical manipulation and coefficient comparison
NEXT STEPS
  • Study the properties of perturbation series in quantum field theory
  • Learn about the techniques for series inversion and coefficient comparison
  • Explore the role of regulators in quantum physics, specifically \( \Lambda \)
  • Investigate advanced mathematical methods for solving infinite series equations
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Physicists, mathematicians, and researchers involved in theoretical physics, particularly those working with perturbation theory and series expansions in quantum mechanics.

zetafunction
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let be m a measures (by expermients) physical quantity and m0 a 'bare' value of these physical quantity , let us suppose that we can expand

[tex]m= m_{0}+f(k,m_{0})+ \sum_{n} u^{n}c_{n}[/tex]

for some finite quantities c_n and [tex]u=log(\Lambda)[/tex] with lambda a regulator

can we then invert the series above to express

[tex]log(\Lambda)= g( f(k,m_{0}) , m , m_{0})[/tex]

how about if instead of logarithms of regulator there are also powers of regulator i mean quantities proportional to [tex]\Lambda ^{k}[/tex]
 
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zetafunction said:
let us suppose that we can expand

[tex]m= m_{0}+f(k,m_{0})+ \sum_{n} u^{n}c_{n}[/tex]

for some finite quantities c_n and [tex]u=log(\Lambda)[/tex] with lambda a regulator

can we then invert the series above to express

[tex]log(\Lambda)= g( f(k,m_{0}) , m , m_{0})[/tex]

One can formally solve every equation [tex]\sum_{n=1}^\infty c_nu^n=x[/tex]
with nonzero c_1 to an equation [tex]\sum_{n=1}^\infty d_nx^n=u[/tex]; simply substitute one into the other and compare coefficients to get recurrence relations.
 

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