A question about Rectilinear motion

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Homework Help Overview

The discussion revolves around a problem in rectilinear motion involving a particle moving under uniform acceleration. The original poster presents a question regarding the average speed of the particle as it covers equal distances in different time intervals.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand why option B is considered correct while they find option C to be straightforward. They express confusion about the reasoning behind option B.
  • Some participants suggest expressing average speeds in terms of initial and final speeds to clarify the reasoning behind option B.
  • Others question the original poster's reasoning and propose an alternative approach to express average speeds for each time interval.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the average speed expressions. Some guidance has been offered regarding the relationship between average speeds and initial/final speeds, but no consensus has been reached on the correctness of option B.

Contextual Notes

Participants are working under the assumption that the particle is speeding up throughout the journey, which may influence their reasoning about the average speeds involved.

Priyadarshi Raj
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Homework Statement


Q:
If a particle moving along a straight line under uniform acceleration covers successive equal distances ( S each) in time intervals t1, t2 and t3 respectively, then the expression for average speed of particle in covering the given distance of 3S is:

Options:
A) (S/t1) + (S/t2) + (S/t3)
B) (S/t1) - (S/t2) + (S/t3)
C) 3S / (t1 + t2 + t3)
D) (S/t1) + (S/t2) - (S/t3)

[You may assume the particle is speeding up for the entire journey]

Here the correct answer are options B and C.
I cannot see how B is correct, although I easily got the option C.

Homework Equations


Average speed = Total distance covered / Total time taken

The Attempt at a Solution


Avg speed = (S + S + S) / (t1 + t2 +t3) = 3S / (t1+t2+t3)
This gives option C.
But I cannot get option B anyhow.
 
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Priyadarshi Raj said:
Avg speed = (S + S + S) / (t1 + t2 +t3) = 3S / (t1+t2+t3)
This gives option C.
Good.

Priyadarshi Raj said:
But I cannot get option B anyhow.
Hint: Each term in B is an average speed. Express those averages in terms of initial and final speed.
 
Doc Al said:
Hint: Each term in B is an average speed. Express those averages in terms of initial and final speed.

Okay then, I believe this is the way:
v2 will be average of v1 and v3
If the avg speeds are v1 = (S/t1) , v2 = (S/t2), v3 = (S/t3), then
Distance traveled during t2 is given by
S = v1t2 + 0.5at22 and also a = (v3 - v1)/t2 [using Newton's laws of motion]
∴ S = v1t2 + 0.5(v3 - v1)t2
⇒ (S/t2) = v1 + 0.5v3 - 0.5v1
⇒ 2(S/t2) = v1 + v3
⇒ 2(S/t2) = (S/t1) + (S/t3)
⇒ (S/t2) = (S/t1) - (S/t2) + (S/t3) = v2
⇒ vavg = v2 = (S/t1) - (S/t2) + (S/t3)

Am I correct?
 
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Priyadarshi Raj said:
Okay then, I believe this is the way:
v2 will be average of v1 and v3
If the avg speeds are v1 = (S/t1) , v2 = (S/t2), v3 = (S/t3), then
I'm not sure I follow your reasoning.

Here's how I would look at it. For interval t1, let the initial and final speeds be v1 and v2. Express the average speed (S/t1) in terms of v1 and v2. Do the same for the other intervals and the total.
 
Doc Al said:
I'm not sure I follow your reasoning.

Here's how I would look at it. For interval t1, let the initial and final speeds be v1 and v2. Express the average speed (S/t1) in terms of v1 and v2. Do the same for the other intervals and the total.

Thank you for helping me.
The problem is solved.
 

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