A question on percentage uncertainty

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The discussion centers on calculating the percentage uncertainty of variable A in the equation D2 = C x N, where C is derived from a graph with a known uncertainty of 25%. The user is confused about whether to double the percentage uncertainty when transitioning from C to A, ultimately leading to a 50% uncertainty in their exam answer. They seek clarification on the rules for propagating errors, particularly for powers in equations. The key point is that the uncertainty should be handled according to the mathematical relationship of the variables involved. Understanding how to propagate errors correctly is essential for accurate calculations in physics.
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Homework Statement



Say we have the equation D2 = C x N where C = A2.
Using a graphical method to find the % uncertainty of C (from graph of D2 against N) which involves working out the gradient which equals C and so forth. This value is 25%.
The question is "what is the percentage uncertainty of A?"

This is actually a question that appeared in an A-level paper i did today and it was the only one that really bamboozled me :confused:.

Homework Equations

The Attempt at a Solution


I realize you don't divide by two;my reasoning being that when asked to calculate the % uncertainty of r in say the equation V = 4/3 x π x r3 the question doesn't explicitly state r3.

So i think that it is between doubling 25% or just leaving it. Now i think it was the latter but in the exam I did indeed double it to 50%.
 
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You are propagating errors of form ##z=x^a## knowing ##x\pm xp_x/100## where ##p_x## is the known percentage error.
So what is the rule for propagating the error on a power?
 
Simon Bridge said:
You are propagating errors of form ##z=x^a## knowing ##x\pm xp_x/100## where ##p_x## is the known percentage error.
So what is the rule for propagating the error on a power?
Multiply the percentage uncertainty by whatever the variable is to the order of?
 
Anyone else?
 
What's wrong with the reply you got so far?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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