A ray crossing 2 media of different indices and energy conservation

Click For Summary
SUMMARY

The discussion centers on the energy conservation principles when a ray crosses two media with different indices of refraction. Participants analyze the intensity of rays (##I_i##) and the solid angles (d##\Omega##) involved in the energy transfer across a surface (dS). The equation referenced (p75) is scrutinized for its representation of energy flow, suggesting that the projection of intensities along the x-axis may imply a vector-like behavior of energy. The consensus indicates that the energy entering the surface is calculated as ##I_1 d\Omega dS##, acknowledging the complexities introduced by reflections.

PREREQUISITES
  • Understanding of ray optics and intensity definitions
  • Familiarity with solid angles and their applications
  • Knowledge of energy conservation principles in physics
  • Basic grasp of vector quantities and their properties
NEXT STEPS
  • Study the derivation and implications of the equation p75 in energy conservation contexts
  • Explore the concept of intensity in ray optics, particularly in varying media
  • Research the effects of reflection on energy transfer in optical systems
  • Learn about the mathematical treatment of solid angles in physics
USEFUL FOR

Physicists, optical engineers, and students studying optics or energy conservation principles in multi-media environments.

Paulpaulpa
Messages
6
Reaction score
2
1627049816908.png


The ##I_i## are the intensity of the rays, in other words energy per surface units per radians by seconds.

The d##\Omega## are the solid angles

The equation p75 isis what I don't understand. I suppose that each side represent the energy going and out of the surface dS but I don't understand why it has this form. It looks like the projection of the intensities along the x-axis, as if energy was a a vector quantity (like the momentum, for which the three components are conserved separately). But only the total energy going through dS should matter and I don't understand why it has this form.

If we say that ##I_1## is independent of the spacetime coordinates and is large enough to wrap around dS, the energy going in should be ##I_1 d\Omega dS## since the surface is totally exposed to the ray. I am probably wrong but I don't know why.
 
Science news on Phys.org
Some energy is reflected.
 
  • Like
Likes   Reactions: sophiecentaur

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 0 ·
Replies
0
Views
517
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
4K