A rim unwinding from a string due to gravity.

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The discussion focuses on a physics problem involving a hoop with a radius of 8 cm and mass of 0.18 kg, which is unwinding a string due to gravity after descending 75 cm. The conservation of energy principle is applied, equating gravitational potential energy (mgh) to the sum of translational and rotational kinetic energy. The moment of inertia (I) of the hoop is considered in the calculations, but initial attempts to solve the problem yield incorrect results. Participants are troubleshooting the equations to correctly determine the angular speed of the hoop and the speed at its center. The conversation emphasizes the importance of accurately applying energy conservation in rotational dynamics.
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Homework Statement




A string is wrapped around a small hoop several times. the radius is 8cm and mass 0.18 kg. the string is released from rest after the hoop has descended 75 cm what is the angular speed of the rotating hoop and the speed at its centre?

Homework Equations




mgh 1/2 Iw^2

The Attempt at a Solution



MGH energy is conserved so mgh=1/2Iw^2
i sub in and solve except this doesn't give the right answer.
 
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If I is the moment of inertia of hoop about its centre then,
intial energy = final energy
GPE = KE of translation + KE of rotation
 
mgh = (1/2)mv^{2} + (1/2)I\omega^{2}
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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