A rocket moves through outer space at 11,000 m/s.

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Homework Help Overview

The discussion revolves around various physics problems, including the motion of a rocket traveling to the Moon, the motion of a rock thrown vertically, the momentum of a shell fired from a cannon, and the forces acting on a person to achieve a specific acceleration. The subject area includes kinematics and dynamics.

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  • Mixed

Approaches and Questions Raised

  • Participants discuss the importance of unit conversion for the distance to the Moon and the need to show initial attempts at solving the problems. There are suggestions to list given information for the rock problem and to consider the velocity at different points in its motion.

Discussion Status

Some participants have offered guidance on unit conversion and the organization of known variables, while others are exploring different aspects of the problems without reaching a consensus on solutions.

Contextual Notes

There is an emphasis on ensuring proper units are used, and participants are reminded to demonstrate their initial attempts at solving the problems, which may be a requirement of the homework guidelines.

Dan Carringto
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A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Earth to the Moon, which is 380,000 km?

A rock thrown straight up climbs for 2.50 s, then falls to the ground. Neglecting air resistance, with what velocity did the rock strike the ground?

What is the momentum of a 30.0 kg shell fired from a cannon with a velocity of 500 m/s?

What forward force must the ground apply to the foot of a 60.0 kg person to result in an acceleration of 1.00 m/s²?
 
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For your first question you need to make sure that everything is in the right units. 1 mile is equal to around 1.6 kilometres.

You need to show you have made some attempt first.
 
Once you have converted you can use...

speed=\frac{distance}{time}
 
for the 2nd question try listing out what is already given to you like the acceleration, time, and velocity final and remember the fact that at the top of the peak the velocity is zero and the velocity at the moment you release the rock is the same as before it hits the ground.

hope it helps with the work
 

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