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A Rocket was launched directly upwards from rest.

  1. Dec 29, 2011 #1
    Hi, I have this particular question, to which i think my method is correct, though the answer from the book which this question is in gives different to mine. Please! any assistance will be very much appreciated!

    Question:

    A Rocket was launched directly upwards from rest. Its motors operated for 30s after it left the launch pad, providing it with a constant vertical acceleration of 6.0m/s during this time. Its motors then switched off.

    Calculate its velocity.

    My method:
    Take upwards as + and g = 9.8

    then u= 0 t= 30 a= -9.8+6 = -3.8

    since V= u +at we get -3.8 X 30 = -114 = 114m/s!

    BUT THE BOOK GIVES THE ANSWER AS 180m/s. (This means they've taken acceleration as 6! But surely acceleration due to gravity is acting downwards, so we need to calculate a resultant acceleration first!)

    thanks
     
  2. jcsd
  3. Dec 29, 2011 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Re: Rocket

    Presumably, the 6 m/s2 is the resultant acceleration, including the effect of gravity. (It wouldn't be much of a rocket if the net acceleration were downward!)
     
  4. Dec 29, 2011 #3
    Re: Rocket

    Ahhhh I get it now! so the motor is providing an acceleration of 15.8m/s^2!!!

    hence resultant acceleration is 15.8-9.8= 6!

    I wouldn't have presumed that was the case, to me 6m/s^2 was the genuine acceleration the motor provided.

    Thank you for your help!
     
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