A Rocket was launched directly upwards from rest.

  • Thread starter Thread starter heartOFphysic
  • Start date Start date
  • Tags Tags
    Rest Rocket
Click For Summary
SUMMARY

A rocket launched directly upwards from rest experiences a constant vertical acceleration of 6.0 m/s² for 30 seconds. The correct calculation for the rocket's velocity at the end of this period is 180 m/s, accounting for the acceleration due to gravity. The initial misunderstanding arose from incorrectly interpreting the acceleration as solely the motor's output without considering the effect of gravity. The resultant acceleration during the rocket's ascent is 15.8 m/s², leading to the correct velocity calculation.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of acceleration due to gravity (9.8 m/s²)
  • Familiarity with vector addition in physics
  • Basic principles of rocket propulsion
NEXT STEPS
  • Study kinematic equations for uniformly accelerated motion
  • Learn about the principles of rocket propulsion and thrust
  • Explore the effects of gravity on projectile motion
  • Investigate how to calculate resultant forces in physics
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding rocket motion and acceleration principles.

heartOFphysic
Messages
18
Reaction score
0
Hi, I have this particular question, to which i think my method is correct, though the answer from the book which this question is in gives different to mine. Please! any assistance will be very much appreciated!

Question:

A Rocket was launched directly upwards from rest. Its motors operated for 30s after it left the launch pad, providing it with a constant vertical acceleration of 6.0m/s during this time. Its motors then switched off.

Calculate its velocity.

My method:
Take upwards as + and g = 9.8

then u= 0 t= 30 a= -9.8+6 = -3.8

since V= u +at we get -3.8 X 30 = -114 = 114m/s!

BUT THE BOOK GIVES THE ANSWER AS 180m/s. (This means they've taken acceleration as 6! But surely acceleration due to gravity is acting downwards, so we need to calculate a resultant acceleration first!)

thanks
 
Physics news on Phys.org


Presumably, the 6 m/s2 is the resultant acceleration, including the effect of gravity. (It wouldn't be much of a rocket if the net acceleration were downward!)
 


Ahhhh I get it now! so the motor is providing an acceleration of 15.8m/s^2!

hence resultant acceleration is 15.8-9.8= 6!

I wouldn't have presumed that was the case, to me 6m/s^2 was the genuine acceleration the motor provided.

Thank you for your help!
 

Similar threads

Replies
1
Views
2K
Replies
3
Views
3K
Replies
13
Views
6K
  • · Replies 10 ·
Replies
10
Views
9K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
9K