A spool of thin wire pivots on a shaft

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SUMMARY

The discussion centers on calculating the energy lost to friction in a pulley system involving a spool of thin wire and a hanging mass of 1.30 kg. The mass falls a distance of 1.7 m, achieving a speed of 0.065 m/s, leading to the calculation of acceleration (0.0036 m/s²), tension (12.24 N), and frictional torque (7.951 N·m). The final energy lost to friction is determined to be 20.83 J. Clarifications regarding the setup and parameters, such as the relevance of the outer radius of the spool, are also sought by participants.

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Homework Statement


Pulley with Friction
A spool of thin wire pivots on a shaft, and there is friction. The wire is pulled by a hanging mass M of 1.30 kg. After falling a distance D= 1.7 m starting from rest, the mass has a speed of 0.065 m/s. Calculate the energy lost to friction during that time.
Inner radius, ri = 0.50 m
Outer radius, r0 = 0.65 m
Icm= 0.96 kg/m2.


The Attempt at a Solution



a=v^2/2*D -> a=0.0036
T=m(g-v^2/2*D) -> T=12.24
alpha=a/r0=(r0*T-Qf)/Icm -> Qf=7.951
theta=D/r0 ->2.62
Ef=theta*Qf -> Ef=20.83

what am I doing wrong?
 
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Hi SereneKi! :smile:

I don't understand the question …

is there a pulley and a spool?

between what surfaces is the friction?

what is the relevance of the outer radius of the spool? :confused:
 

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