A stone is dropped from the top of a cliff

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SUMMARY

A stone dropped from the top of a cliff takes 3.30 seconds to reach the ground. Using the equation of motion h = v_0 t + ½gt², where the initial velocity (v_0) is 0 and g is the acceleration due to gravity (approximately 9.81 m/s²), the height of the cliff can be calculated. Substituting the values, the height h is determined to be approximately 53.5 meters. This calculation illustrates the application of kinematic equations in physics.

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  • Understanding of kinematic equations in physics
  • Basic knowledge of acceleration due to gravity (g = 9.81 m/s²)
  • Ability to perform algebraic calculations
  • Familiarity with the concept of free fall
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thschica
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A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.30 s. How high is the cliff?
 
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Use the equations of motion:
h = v_0 t + \frac{1}{2}gt^2
Where v_0 is the initial velocity (=0) and g is the acceleration due to gravity.
 

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