A subspace spanned by polynomials 1 and x

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SUMMARY

The discussion focuses on finding the orthogonal projection of the polynomial p(x) = 1 + x² onto the linear subspace W spanned by the polynomials {1, x}. The inner product is defined as = integral (p(x) * q(x), x, 0, 1). To solve for the orthogonal projection, one must establish two linear equations based on the condition that the difference between p(x) and the projection is orthogonal to both basis vectors of W.

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1. Let W be the linear subspace spanned by the polynomials 1 and x. Find an orthogonal projection of the polynomial p(x) = 1+x^2 to W. Find a basis in the space W(perp)


My problem is that I don't know how to represent W as a matrix so that I could apply the orthogonal projection formula.

Would it simply be [1, x] or [1 ; x]?

Thanks!
 
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{1,x} is certainly a basis for W. But to define orthogonal you need to say what the inner product is.
 
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Remember, the dot product (or inner product) should be equal to 0 if they are orthogonal.
 
Dick said:
{1,x} is certainly a basis for W. But to define orthogonal you need to say what the inner product is.

If the inner product is given by: <p(x),q(x)> = integral (p(x)*q(x), x, 0, 1), how would i go about solving this problem?

(This is not my homework by the way, I'm studying for my final exam which is tomorrow, but I just can't figure out this problem.)

Thank you.
 
If a*1+b*x is a point in W that is the orthogonal projection, you want that <(1+x^2)-(a*1+b*x),1>=0 and <(1+x^2)-(a*1+b*x),x>=0. That would say that the difference between (1+x^2) and (a*1+b*x) is perpendicular to all of the vectors in W which is the span of {1,x}, wouldn't it? It's just two linear equations in the unknowns a and b.
 

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