A Thermodynamic (supposed to be easy) Problem

  • Thread starter Thread starter Arshad_Physic
  • Start date Start date
  • Tags Tags
    Thermodynamic
Click For Summary

Discussion Overview

The discussion revolves around a thermodynamic problem involving a steel tank that needs to be submerged in the ocean by adding concrete to its bottom. Participants explore the principles of buoyancy and weight to determine the amount of concrete required for the tank to float at a specified depth.

Discussion Character

  • Homework-related, Mathematical reasoning, Conceptual clarification

Main Points Raised

  • One participant states the problem and expresses uncertainty about applying buoyancy principles, mentioning the density of water and the tank.
  • Another participant suggests that to achieve the desired submersion, the weight of the concrete must equal the weight of the water displaced by the submerged portion of the tank.
  • A third participant calculates the volume of the tank and the corresponding weight of water displaced, concluding that the total weight needed for the tank to be submerged is 29,910 kg, which includes the weight of the tank and the concrete.
  • A later reply expresses gratitude for the assistance provided in the discussion.

Areas of Agreement / Disagreement

Participants present different calculations and approaches to the problem, indicating that multiple competing views remain regarding the correct amount of concrete needed. The discussion does not reach a consensus.

Contextual Notes

Some assumptions regarding the buoyancy principle and the calculations of weight and volume may be missing or not fully articulated, leading to potential discrepancies in the proposed solutions.

Who May Find This Useful

Students or individuals interested in thermodynamics, buoyancy principles, and problem-solving in physics may find this discussion relevant.

Arshad_Physic
Messages
50
Reaction score
1

Homework Statement



A steel tank of cross sectional area 3 m2 and height 16 m weighs 10,000 kg and is open at the top. We want to float it in the ocean so that it is positioned 10 m straight down by pouring concrete into its bottom. How much concrete should we use?


Homework Equations





The Attempt at a Solution



I have thought about Potential gravity. I have looked that Waters density is 997 kg/m3. I got this container's ensity (It is 208.33) but I just don't know how to solve it! :) I don't remember much about buoyancy and Bouyancy might be the thing needed here!

Answer is 19910 kg...Please help! :)
 
Physics news on Phys.org
¿you need to have 10 meters down water and 6 up water?

Then you have to put inside the tank same weight as the weight of water evacuated. (Arquimides)

Volume of the tank inside water (section X 10 m) ---> Volume of water evacuated ----> density of water -----> mass of water evacuated = 10000kg of the tank + x kg of concrete

¿It can be?
 
30 m^3 of tank ------> 30 m^3 of water ----- x 997kg/m^3 -----> 29910 kg

Then your tank have to weight 29910; 10000 of the tank and 19910 of the concrete
 
Awesome! THanks sooo much! :)
 

Similar threads

  • · Replies 49 ·
2
Replies
49
Views
5K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
13
Views
3K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 21 ·
Replies
21
Views
24K