A Uniform Rod Is Attached To A Point With A String---Moments

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Priyadarshini
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Homework Statement


upload_2015-8-20_20-14-58.png


Use the principle of moments and take moments about A to show that the weight of the object O is 19 N.

Homework Equations



Moment=Force x perpendicular distance

The Attempt at a Solution


Vertical component of tension= TsinA
= 30sin50
=23N
(8.5 x 0.6) = (9.8M-23) x 1.2
5.1/1.2 = 9.8M-23
9.8M=27.25
As w=mg, the W= 27.25N
But the answer is supposed to be 19N[/B]
 
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Priyadarshini said:
Vertical component of tension= TsinA
= 30sin50
=23N
(8.5 x 0.6) = (9.8M-23) x 1.2
5.1/1.2 = 9.8M-23
9.8M=27.25
As w=mg, the W= 27.25N
But the answer is supposed to be 19N
You have made an error in balancing moments . Which moment acts in which direction ?
 
Qwertywerty said:
You have made an error in balancing moments . Which moment acts in which direction ?
One acts clockwise from point B, I am not so sure about the other. Does it act anticlockwise from point A or does it act at the centre?
 
In which direction does gravity exert a force on M ? Is it in the direction of tension or the rod ?
 
Qwertywerty said:
In which direction does gravity exert a force on M ? Is it in the direction of tension or the rod ?
It exerts a force in the direction of the rod.
 
So should it's moment add to that of the rod's , or should that of the tension's ?
 
Qwertywerty said:
So should it's moment add to that of the rod's , or should that of the tension's ?
It should act to that of the rod.
 
And what have you done in your original solution ?

Hope this helps ,
Qwertywerty .
 
Qwertywerty said:
And what have you done in your original solution ?

Hope this helps ,
Qwertywerty .
Thanks!