A variation on a classic problem

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The discussion centers on the exploration of the diophantine equation S(n) + 1 = m^2, where S(n) represents the sum of squares from 1 to n. The only confirmed solutions are for n = 47 and n = 48, with S(48) being one less than a perfect square. The conversation also touches on the historical context of square pyramidal numbers, specifically that the only square pyramidal numbers which are also perfect squares are 1 and 4900. The inquiry raises the possibility of whether the absence of additional solutions constitutes a theorem, linking it to the classical cannonball problem.

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Most number theorists will be familiar with the result conjectured in the 19th century and proved in the 20th century that the only square pyramidal numbers that are square numbers are 1 and 4900 (the sum of the squares from 1^2 to 24^2 = 70^2).

While discussing this, it was pointed out to me that the sum of the squares 1^2 up to 48^2 is 1 short of a perfect square. A little investigation found the same was true of the sum up to 47^2, but I did not find any other small examples.

This seems intriguing, especially as 48 is double 24. My best guess is that someone must have noticed this 100 years ago, but I have not confirmed this.

The question is are there any solutions of the diophantine equation:

1^2 + 2^2 + ... N^2 = M^2 - 1

other than N=47 and N=48?
 
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Elroch said:
Most number theorists will be familiar with the result conjectured in the 19th century and proved in the 20th century that the only square pyramidal numbers that are square numbers are 1 and 4900 (the sum of the squares from 1^2 to 24^2 = 70^2).

While discussing this, it was pointed out to me that the sum of the squares 1^2 up to 48^2 is 1 short of a perfect square. A little investigation found the same was true of the sum up to 47^2, but I did not find any other small examples.


What about 1 more than a perfect square (N=2)? Or 4 short (N=7,N=9,N=191,N=192,N=994)?
Wouldn't they be considered 'small' examples?
 
Well, they are small answers, but to different questions!

Call S(n) = 1^2 + 2^2 + ... + n^2 for convenience.

The question as posted was looking for natural numbers n and m such that

S(n) + 1 = m^2

I have as yet failed to find any solutions other than the first two.

I did find a nice sequence of examples of adjacent pairs of numbers where the sum is n^2 short of a perfect square. Some of these are in your examples:

Look at n = 48*k^2 and 48*k^2-1

What I wonder is whether the lack of other solutions to the original problem is a theorem, and whether this is related to the old cannonball problem, where the sum has to be an exact square (and the only solutions are N=1 and N=24).
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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