About an example related to angular momentum in a textbook

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SUMMARY

The discussion centers on the relationship between angular momentum (L) and angular velocity (ω) as presented in a physics textbook. The user expresses confusion regarding the claim that L and ω generally have different directions, despite the mathematical relationship L = m||r||²ω suggesting they are parallel. The explanation clarifies that while angular momentum vectors for two point masses connected by a rigid bar point in the same direction, the angular velocity vector is perpendicular to the line connecting the masses, thus illustrating their differing orientations.

PREREQUISITES
  • Understanding of angular momentum (L = rxmv)
  • Familiarity with angular velocity (ω = rxv/||r||²)
  • Basic knowledge of rigid body dynamics
  • Concept of vector directionality in physics
NEXT STEPS
  • Study the relationship between angular momentum and angular velocity in rigid body dynamics
  • Explore vector mathematics in physics, focusing on vector directionality
  • Learn about the principles of rotational motion and torque
  • Investigate examples of angular momentum in multi-body systems
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Students studying physics, particularly those focusing on mechanics, educators seeking to clarify concepts of angular momentum and angular velocity, and self-learners in the field of classical mechanics.

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Hey I either have the worst physics textbook in the history of physics textbooks or i can't understand a topic.I'd appreciate if you help me decide which is it.
(Pic related is the image of the example)
First let's agree on the symbols let's call angular velocity: \omega = \frac{rxv}{||r||^2} , angular momentum L=rxmv and Lineal Momentum:P=mv. Being that defined, the book attemps to proof that L and [math]\omega[/math] have generally different directions, here is the first problem i encountered, for what i know m||r||^2\omega = L being m||r||^2 That means that Angular Velocity and Angular Momentum are parallel therefore have the same direction, the example proceed as following: 2 puntual mass are united by a rigid bar of despicable mass, therefore both have the same angular momentum. the momentum of body 1 is L_1 = r_1xm_1v_1 and it explicitly say that it's easy to see that it's contained in the plane given by P_1 P_2 \omega (which i fail to see) being the direction perpendiculat to the line that unites P_1 with P_2 and that L_2 Has the same direction that L_1. Therefore the Angular Impulse make an angle of \frac{\pi}{2}-\alpha with the axis of rotation(\omega). Well that'd be an example i'd really appreciate if someone can clarify my doubts, i don't have a teacher to ask since i study by my own.
Here is a picture of the example:
2012-03-10 22.09.43.jpg
 
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It looks like your textbook is trying to explain why the angular momentum and angular velocity vectors are usually not in the same direction. The angular momentum vector is a vector that points from the point mass to the axis of rotation, and its magnitude is the product of the mass and the distance from the axis of rotation times the velocity. The angular velocity vector points along the axis of rotation, and its magnitude is the product of the radius and the velocity.In the example, they explain how if two point masses are connected by a rigid bar, then the angular momentum vector of each point mass will be in the same direction, but the angular velocity vector will not be in the same direction. This is because the angular velocity vector is always perpendicular to the line connecting the two point masses, and the angular momentum vector is always in the plane defined by the two point masses and the angular velocity vector.This example should make it clear why the angular momentum and angular velocity vectors usually do not have the same direction. Hope this helps!
 

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