About mixed integral for perturbation in hydrogen atom

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ntusg
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Homework Statement



During my calculation of hydrogen atom perturbation, I need to integral below in cartesian coordinate. It is given that below integral can be transformed.

Homework Equations



Triple integral from negative infinity to infinity of x squared e to the minus r, dx dy dz, equals one third times the integral from 0 to infinity and from 0 to pi and from minus pi to pi of r squared e to the minus r, times r squared sin theta, dr d theta d phi.


Anyone could help to see what will the transformed integral in polar coordinate if the left-hand-side integral were changed to r*x^2*exp(-r) instead of x^2*exp(-r).

Thanks.

The Attempt at a Solution

 
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They are just using that the integral of x^2*exp(-r), y^2*exp(-r) and z^2*exp(-r) are all equal by symmetry. So if you add them all together you get r^2*exp(-r). Hence the '1/3'. Putting another r in front of x^2*exp(-r) doesn't stop you from doing the same thing.
 
Hi Dick, I just got it, and it only about rewriting dV in Cartesian to the polar coordinate.
Thanks for the help!