About Relaxation Time Approximation

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SUMMARY

The discussion centers on the Relaxation Time Approximation as described in Ashcrift & Mermin's chapter 13. It specifically addresses the equilibrium distribution of electrons, represented by the formula g_n (r,k,t)=g_n^o (r,k)=\frac {1}{ exp^{(\epsilon_n (k) -\mu (r))/kT} +1}, and the implications of collisions on the distribution function. The key point is that for the distribution function to remain unchanged, any electrons that leave a specific band must be compensated by an equal number entering from other bands, maintaining a constant average population in each band.

PREREQUISITES
  • Understanding of statistical mechanics and thermal equilibrium concepts
  • Familiarity with electron band theory and wave vectors
  • Knowledge of the Relaxation Time Approximation in solid-state physics
  • Ability to interpret mathematical expressions in physics, particularly in the context of distribution functions
NEXT STEPS
  • Study the derivation of the Relaxation Time Approximation in solid-state physics
  • Explore the implications of thermal equilibrium on electron distributions in semiconductors
  • Learn about the Boltzmann transport equation and its applications in statistical mechanics
  • Investigate the role of collisions in altering electron distributions in various materials
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Physicists, materials scientists, and students studying solid-state physics who are looking to deepen their understanding of electron behavior in thermal equilibrium and the effects of collisions on distribution functions.

hokhani
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I have seriously stocked in the subject below.

According to Ashcrift & Mermin (chapter 13):

If the electrons about r have equilibrium distribution appropriate to local temperature T(r),
g_n (r,k,t)=g_n^o (r,k)=\frac {1}{ exp^{(\epsilon_n (k) -\mu (r))/kT} +1} (formula 13.2) then collisions will not alter the form of distribution function. We know in the time interval dt a fraction \frac{dt}{\tau_n(r,k)} of electrons in band n with wave vector k near position r will suffer a collision that does alter their band index and/or wave vector. If the above form of distribution function is nevertheless to be unaltered, then the distribution of those electrons that emerge from collisions into band n with wave vector k during the same interval must precisely compensate for this loss. Thus:
g_n (r,k,t)=\frac{dt}{\tau_n(r,k)} g_n^o (r,k) (formula 13.3)

I don’t know how is 13.3 obtained.

In fact I don’t know what the text means by form of distribution function in the expression “collisions will not alter the form of distribution function”? On one hand if the electrons near r which left the point (n,k) due to collision are precisely compensated then at a specific (r,k) the distribution function doesn’t have to change and the expression means that g_n (r,k,t)=g_n^o (r,k) which is 13.2. on the other hand using this interpretation, near position r at time interval dt due to collisions\frac{dt}{\tau_n(r,k)} electrons will leave the point (r,n,k) to another point say (r,n^\prime,k^\prime) so that dg_n (r,k,t)=g^0_n{\prime} (r,k^\prime,t^\prime)- g_n^0 (r,k,t) where t^\prime=t+dt.

However if we were to accept this, how can we consider the dg_n as the number of electrons which have left (r,n,k) toward (r,n\prime,k\prime) due to collision at time interval dt namely\frac{dt}{\tau_n(r,k)} g_n^o (r,k)? If so, we necessarily must have just prior to collision g^0_n(r,k,t)= g^0_n\prime(r,k\prime,t) so that this amount of electrons that enter there, perform a change in distribution function as much as\frac{dt}{\tau_n(r,k)} g_n^o (r,k)!

Could anyone please help me?
 
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Hmmm, the definition of thermal equilibrium is that (a) because of the finite temperature collisions occur and (b) in equilibrium the (average) situation is static, i.e. time derivatives of statistical properties vanish.

For this to be true, every electron scattered away from band n/wave vector k must be replaced by an electron coming from a different band/wave vector. The population of each band/wave vector therefore stays (on average) constant. With that the form of the distribution function remains constant.
 

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