Absolute Max/Min of a Trig Function

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SUMMARY

The discussion focuses on finding the maximum and minimum values of the trigonometric function f(t) = 2cos(t) + sin(2t) over the interval [0, π/2]. The process involves calculating the derivative f'(t) = 2cos(2t) - 2sin(t) and setting it to zero to identify critical points. The critical points are found by solving the equation cos(2t) - sin(t) = 0. To simplify this, the identity cos(2t) = 1 - 2sin²(t) can be used, transforming the problem into a solvable quadratic equation in terms of sin(t).

PREREQUISITES
  • Understanding of trigonometric functions and their properties
  • Knowledge of derivatives and critical points
  • Familiarity with trigonometric identities, specifically cos(2t)
  • Ability to solve quadratic equations
NEXT STEPS
  • Study the application of trigonometric identities in calculus
  • Learn how to solve quadratic equations derived from trigonometric functions
  • Explore the concept of critical points in the context of trigonometric functions
  • Practice finding maxima and minima of various trigonometric functions over defined intervals
USEFUL FOR

Students and educators in calculus, mathematicians focusing on trigonometric analysis, and anyone seeking to understand optimization of trigonometric functions within specified intervals.

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I am having some issues with going about finding the max and min of trig functions over a set interval. Normally with finding the max and min of a function over an interval the first thing that I do is find the derivative of that function, Then i set the derivative to 0 and solve to find the critical points. Now this is where I run into problems...

Ex. Find the Max/Min values of f on the interval [0,pi/2] f(t)=2cos(t)+sin(2t)My work:

f(t)=2cos(t)+sin(2t) "the original function"

f'(t)=2cos(2t)-2sin(t) "I found it's derivative"

0=2cos(2t)-2sin(t) "finding where f' is equal to 0"

0=cos(2t)-sin(t) "simplified"

But now what? With a normal function you get a nice x=?,?,? ...

SO how can i find the critical values for a trig function and how can I then find the Max and Min over a set interval?
 
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You can use trig identities to rewrite \cos(2t) entirely in terms of \sin^2t. This will leave you with a quadratic equation in terms of \sin t to solve.
 
So you need to solve cos(2t)-sin(t)=0. Is suggest you first use the formula cos(2t)=1-2sin²(t). Then you have a quadratic equation in sin(t) which can be solved with the usual methods...
 

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