Absolute pressure at an ocean depth

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SUMMARY

The pressure at an ocean depth of 550 meters is calculated to be 5,609,880 Pascals (Pa), considering a sea water density of 1,022 kg/m³ and an atmospheric pressure of 101.3 kPa. To determine the force exerted by the water on a circular submarine porthole with a diameter of 32.0 cm, one must first calculate the area of the porthole and then apply the formula for pressure, which is force divided by area. This results in the necessary force to counterbalance the water pressure at that depth.

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jenha14
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a) Calculate the pressure at an ocean depth of 550 m. Assume that the density of sea water is 1022 kg/m3 and that the air above exerts a pressure of 101.3 kPa.
b) At this depth, what force must the frame around a circular submarine porthole having a diameter of 32.0 cm exert to counterbalance the force exerted by the water?

I found the answer for (a) to be 5609880 Pa, but I am stuck on part (b).
 
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Assuming the inside of the sub is at atmospheric pressure all you need is the water pressure at that depth.
Since pressure is force / area. You have the pressure,you can get the area of the porthole so hat is the force?
 

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