- #1
member 731016
Dose someone please know why they have the absolute value bars in this derivation?
many thanks!
many thanks!
Undergrad Absolute value bars in dot product derivation
- Thread starter member 731016
- Start date
Click For Summary
The absolute value bars in the dot product derivation represent the length of the vector rather than the absolute value of a number. This notation is used because the length of a vector is always positive. The convention of using absolute value bars was more common in earlier vector mathematics texts, while modern texts often prefer double v-bar notation. Understanding this distinction is crucial for correctly interpreting vector operations. The discussion highlights the evolution of notation in vector mathematics.
Hello!
In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way:
I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true?
And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...
Similar threads
Undergrad
Dot product in Euclidean Space
- · Replies 16 ·
High School
Confused about dot product multiplication
- · Replies 33 ·
- · Replies 12 ·
- · Replies 14 ·
- · Replies 4 ·
- · Replies 18 ·
- · Replies 5 ·
- · Replies 1 ·