High School What is the cross product of two vectors?

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The cross product of two vectors results in a third vector that is orthogonal to both original vectors and has a magnitude equal to the area of the parallelogram formed by them, calculated as |A||B|sin(Θ). This operation is non-commutative, meaning that switching the order of the vectors changes the direction of the resulting vector. The direction of the cross product follows the right-hand rule, providing a consistent way to determine orientation. The cross product is particularly useful in physics, especially in electromagnetism, where it helps define vector fields and forces. Understanding the cross product's geometric interpretation enhances its application in various mathematical and physical contexts.
  • #31
etotheipi said:
@Mark44 I think what @wrobel is saying, is that the cross product of two vectors is not itself a vector, because it does not transform like a vector. To get the right transformation properties (i.e. to turn it into a vector) you also need to multiply by the determinant of the transformation matrix. But before you do that it's still just a tensor density.
Here's what wikipedia has to say (https://en.wikipedia.org/wiki/Cross_product#:~:text=In mathematics, the cross product or vector product,is denoted by the symbol {displaystyle%20times%20}:
Given two linearly independent vectors a and b, the cross product, a × b (read "a cross b"), is a vector that is perpendicular to both a and b, and thus normal to the plane containing them.
Cross products are typically introduced in intro physics courses and in precalculus mathematics courses -- and there is not usually any mention of tensors.
 
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  • #32
I mean, I prefer to think of the cross product as a pseudovector, but I guess it’s probably not helpful for OP.

I think the most succinct explanation of the cross product at this level probably comes from the volume formula, as others have said. Namely, that the “signed volume” ##V(\mathbf{a,b,c})## of a parallelepiped with sides ##\mathbf{a,b,c}## is linear in each of its arguments, and that ##\mathbf{a\times b}## is the unique (pseudo)vector such that ##V(\mathbf{a,b,c})=(\mathbf{a\times b})\cdot\mathbf{c}.## While most of us know from linear algebra that in any given basis such a vector exists, it can be verified in Cartesian coordinates.
 
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  • #33
suremarc said:
I mean, I prefer to think of the cross product as a pseudovector, but I guess it’s probably not helpful for OP.
I agree. Several posts that are well beyond B-level have been removed. Since the OP has not returned since his initial post, I'm closing this thread. If he/she has additional questions that haven't been addressed in this thread, I will reopen it.
 
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