One kg of human body contains about 0.2% potassium of which 0.0117% is potassium-
40 (40K). 40K is radio active and in 89% of the time the product of the decay is a gamma ray of energy
1.46 MeV. If we assume that all of these gamma rays deposit their energy
in the body calculate the following:
1. Absorbed dose in the body
Absorbed dose is equal to the amount of energy absorbed per unit mass, and equivalent dose = RBE * absorbed dose
The Attempt at a Solution
Well, I worked out that 0.00234% of the body contains the radioactive substance.(0.2*.0117). Then I converted the 1.46MeV to Joules, giving me 2.339x10^-13 J. THen I multiplied this by 42736 (which is 100/0.00234) to see how much is acting on the whole unit mass of the body (1kg) and I got absorbed dose = 1.02x10^-6 Gy.
Is my working way off?