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AC Circuits II: AC Power Generator

  • Thread starter OsDaJu
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  • #1
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Homework Statement



A An AC generator supplies an rms voltage of 110 V at 60.0 Hz. It is connected in series with a 0.300 H inductor, a 5.80 μF capacitor and a 236 Ω resistor.
What is the impedance of the circuit?

B What is the rms current through the resistor?

C What is the average power dissipated in the circuit?

D What is the peak current through the resistor?

E What is the peak voltage across the inductor?

F What is the peak voltage across the capacitor?

G The generator frequency is now changed so that the circuit is in resonance. What is that new (resonance) frequency?

Homework Equations



Z=[R^2+(XL-Xc)^2]^(1/2)
XL=2pifL
Xc=1/(2pifc)

Part E: VL=[(2^.5)*Vrms]/Z
Part F: VL=[(2^.5)*Vrms]/Xc

The Attempt at a Solution



I need help for part E and F

I substituted the numbers in the equation and I got the wrong answer. Can someone point me in the right direction?

Xc=457.34
Vrms=110
Z=4.17×10^2
 
Last edited:

Answers and Replies

  • #2
rl.bhat
Homework Helper
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5
Vrms across C = Irms* Xc
Now what is the relation between peak voltage and rms voltage?
 
  • #3
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Thank you!
 

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