AC Power RC series circuit low pass filter, find frequency given gain.

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SUMMARY

The discussion focuses on calculating the cutoff frequencies for a series AC power RC circuit configured as both a low pass and high pass filter. Given a 600 ohm resistor and a 73 nF capacitor, the calculated frequency for the low pass filter to achieve a gain of 0.25 is 5895 Hz, while the high pass filter configuration yields a frequency of 88424 Hz. The formulas used for these calculations are Vout/Vin = R / (R^2 + (1/ωC)^2)^(1/2) for the low pass filter and Vout/Vin = (1/ωC) / (R^2 + (1/ωC)^2)^(1/2) for the high pass filter.

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dfs730
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1. You have a series circuit consisting of a ac power supply, a 600 ohm resistor and a 73 nF capacitor.
If the circuit is configured as a low pass filter, what frequency will cause the gain to be 0.25?

2. If the circuit is configured as a high pass filter, what frequency will cause the gain to be 0.25?


Vout/Vin = R / (R^2 + (1/ωC)^2)^(1/2) low pass filter


Vout/Vin = (1/ωC) / (R^2 + (1/ωC)^2)^(1/2)


I tried to sub in for R,C, and gain (Vin/Vout) and got 5895 Hz for #1 and 88424 Hz for #2

any suggestions?
 
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Check your RC layout for the low pass filter. The capacitor should be in a position to short out high frequencies, and allow low frequencies to pass.
 

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