Accelerating protons and antiprotons for pair production?

[Tangeton]

Okay so I have a problem with what my textbook is saying.

It defined pair production as a process in which a photon of electromagnetic energy is converted to a pair of particles.

But then it gave the discovery of an antiproton. Which was when a proton was accelerated to 6MeV and collided into a stationary proton, making one antiproton and 3 protons.

So, does this p + p --> p + p + antip process count as pair production? In which case, would the definition of pair production be a bit different?

Also, I found a website on which it says that ''sometimes, a pair of particles annihilates, but then the photon produces another pair of particles.'' When it comes the the first line, is this basically when a pair annihilates, but then the photon still has a lot of energy due to the extra kinetic energy of the particle and its antiparticle, meaning that when it passes close to a nucleus?

Edit: It also says that a antip + p = n + antin Is this besically an example of what I just wrote above (particles annihilate but then the photon produces another pair of particles)?

Sorry for lots of questions and thank you for your time.

 

[Vanadium 50]

p + p --> p + p + antip

Does that conserve charge?

 

[Tangeton]

Does that conserve charge?

oooo whoops it's p + p --> p + p + p + antip and well it doesn't look like it does conserve charge, but what has that got to do with anything? Says here it does happen so I am not trying to disprove it?

 

[Vanadium 50]

but what has that got to do with anything?

Charge is always conserved. If you write down a reaction that doesn't, it's wrong.

 

[Tangeton]

Charge is always conserved. If you write down a reaction that doesn't, it's wrong.

Well yes I know but charge is conserved here. I just wrote the wrong equation by accident.