Acceleration and Distance problem

  • Thread starter The Tutor
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  • #1
The Tutor
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Homework Statement


A turtle is moving with constant acceleration along a straight ditch. He starts his stopwatch as he passes a fence post and notes that it takes him 10s to reach a pine tree 10m further along the ditch. As he passes the pine tree, his speed is 1.2m/s. How far was he from the fence post when he started from rest?

Homework Equations


V22=V12+2a[tex]\Delta[/tex]d
[tex]\Delta[/tex]d=V1[tex]\Delta[/tex]t+1/2a([tex]\Delta[/tex]t)2
[tex]\Delta[/tex]d=V2[tex]\Delta[/tex]t-1/2a([tex]\Delta[/tex]t)2


The Attempt at a Solution



So I found out acceleration using the third equation, which is .04 m/s2. So now I believe I have to figure out the velocity at the fence post, which comes to 0.8 m/s. I don't know what to do after that.
 

Answers and Replies

  • #2
Bhumble
157
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You've already done all the work. All they are asking you is to solve for the distance the turtle traveled from rest to the fence post. Just use equation 1 with V1 = 0, V2 = 0.8 m/s, and a = .04 m/s^2.
 
  • #3
The Tutor
12
0
You've already done all the work. All they are asking you is to solve for the distance the turtle traveled from rest to the fence post. Just use equation 1 with V1 = 0, V2 = 0.8 m/s, and a = .04 m/s^2.

Oh. Yeah I see that now thanks.
 

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