# Acceleration and Distance problem

The Tutor

## Homework Statement

A turtle is moving with constant acceleration along a straight ditch. He starts his stopwatch as he passes a fence post and notes that it takes him 10s to reach a pine tree 10m further along the ditch. As he passes the pine tree, his speed is 1.2m/s. How far was he from the fence post when he started from rest?

## Homework Equations

V22=V12+2a$$\Delta$$d
$$\Delta$$d=V1$$\Delta$$t+1/2a($$\Delta$$t)2
$$\Delta$$d=V2$$\Delta$$t-1/2a($$\Delta$$t)2

## The Attempt at a Solution

So I found out acceleration using the third equation, which is .04 m/s2. So now I believe I have to figure out the velocity at the fence post, which comes to 0.8 m/s. I don't know what to do after that.

## Answers and Replies

Bhumble
You've already done all the work. All they are asking you is to solve for the distance the turtle traveled from rest to the fence post. Just use equation 1 with V1 = 0, V2 = 0.8 m/s, and a = .04 m/s^2.

The Tutor
You've already done all the work. All they are asking you is to solve for the distance the turtle traveled from rest to the fence post. Just use equation 1 with V1 = 0, V2 = 0.8 m/s, and a = .04 m/s^2.

Oh. Yeah I see that now thanks.