k0k
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Homework Equations
a=F/m
Ek= 1/2mv^2
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Not exactly sure how to go through with this..
I tried finding velocity with the given kinetic energy, but am unsure what to do next.
The discussion centers on the relationship between acceleration, kinetic energy, and the concept of closest approach in particle physics. The equations used include acceleration (a = F/m) and kinetic energy (Ek = 1/2mv^2). Participants express confusion regarding the maximum kinetic energy of a particle as it approaches a nucleus, particularly in the context of repulsive forces between like charges. The key takeaway is that kinetic energy is maximized at the point of closest approach, and understanding the forces at play is crucial for determining the particle's velocity and energy changes.
PREREQUISITESThis discussion is beneficial for physics students, educators, and anyone interested in the principles of particle dynamics and energy transformations in electrostatic contexts.
k0k said:Um, the kinetic energy is at it's maximum when it's approaching the nuclues?