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Acceleration and Kinetic Energy

  1. Jan 21, 2013 #1

    k0k

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    k30wsi.png


    2. Relevant equations

    a=F/m
    Ek= 1/2mv^2
    ---
    Not exactly sure how to go through with this..
    I tried finding velocity with the given kinetic energy, but am unsure what to do next.
     
  2. jcsd
  3. Jan 21, 2013 #2

    tms

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    What has happened to the kinetic energy at the point of closest approach? Where is the point of closest approach?
     
  4. Jan 22, 2013 #3

    k0k

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    Um, the kinetic energy is at it's maximum when it's approaching the nuclues?

    Wait.. so is the kinetic energy given to me, is the Ek at the beginning I believe. Not sure how that'll help me though.
     
  5. Jan 22, 2013 #4

    haruspex

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    How fast is the particle moving when at its closest to the nucleus? What has been the change in KE? Where has the energy gone? Can you determine the distance of closest approach?
     
  6. Jan 22, 2013 #5

    tms

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    Are you sure about that? You have a positive charge approaching another positive charge? Is the force attractive or repulsive?
     
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