Acceleration at the center of circle

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SUMMARY

The discussion centers on calculating the acceleration at the center and at a point 1 cm from the center of a circle with a radius of 2 cm rotating at 1000 RPM. It is established that the acceleration at the center is zero, as it does not move. For the point 1 cm from the center, the correct formula to use is a = ω²r, where ω is the angular velocity derived from the rotation speed. The participants noted discrepancies in the provided acceleration value of 2 m/s², which is inconsistent with theoretical expectations.

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songoku
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Homework Statement


A circle with radius 2 cm rotates at 1000 rpm and the acceleration at the rim is 2 ms-2.
a. What is the acceleration at the center ?
b. What is the acceleration at 1 cm from the center ?


Homework Equations





The Attempt at a Solution


a. The acceleration will be zero because the center doesn't move?

b. a = ω2r = 2πf*r = 2π * 1000/60 * 2 x 10-2 = 2/3 π ms-2. Is this right?

Thanks
 
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Your answer for a seems to be right. The problem is that the acceleration at the rim of a circle with radius 2 cm that rotates with 1000 rpm is more than 100 times as high as [itex]2 m s^{-2}[/itex]
I don't see why the acceleration is given at all in the problem.

For part b you use [itex]\omega[/itex] instead of [itex]\omega^2[/itex] and a radius of 2 cm instead of 1 cm
 
Hi willem

Yeah, my mistake...now I know it's not a good idea to post question at 2 AM..

I also agree that the information given doesn't match the theoretical calculation...something wrong with the question...

Thanks a lot !
 

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