Acceleration given velocity and distance

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 4K views
swede5670
Messages
78
Reaction score
0

Homework Statement


A car traveling at 90 km/h strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.86 m. What was the average acceleration in g's of the driver during the collision?

Homework Equations


The Attempt at a Solution


The acceleration in m/s/s is -363.37 but I tried dividing by 9.8 and I got -37.05 g's but evidently that's wrong. I'm not sure what I'm missing here, I converted the km/h into m/s/s then got the correct acceleration then devided by 9.81. Is there a rule that I didn't use? Is there a limit on negative gs?
 
Last edited:
on Phys.org
You are right, the acceleration is -363.37 m/s/s.

I'm not a hundred percent sure, but I think -37.08 g's is actually correct. Because if one g is worth 9.8 m/s/s, and you had positive 37.08 of them, your acceleration would be in the positive direction. But it's not... so I see no problem with having a negative number there.

Is there another reason you think -37 g's is wrong?