# Deriving an equation for displacement and acceleration (given velocity)

## Homework Statement

For 0<t<1, v(t) = t +3
For 1<t<2, v(t) = 5-t
Assume x(o)=0

A) Draw corresponding displacement and acceleration diagrams.
B) Determine the equation for each segment

## Homework Equations

Acceleration is the derivative of velocity.
Velocity is the derivative of displacement.

## The Attempt at a Solution

I can draw the acceleration diagram and write the equation so no problem there.
My problem is drawing the displacement diagram.

I got the equations for displacement. They are:
For 0<t<1
t2/2 + 3t + C
For 1<t<2
5t - t2/2 + C

I cannot figure out how to evaluate that constant and plot that on a graph. Also, my teacher mentioned finding the area under the original curve and plotting that. The area = 3.5but that's not a point to plot. What do I dO?

## Answers and Replies

Related Introductory Physics Homework Help News on Phys.org
minger
Science Advisor
It seems to me that you have everything except the constants of integration. You are told to assume that x(0) = 0, meaning that at time of zero, you have no displacement. Plug it in to get your constant.

tiny-tim
Science Advisor
Homework Helper
For 0<t<1, v(t) = t +3
For 1<t<2, v(t) = 5-t
Assume x(o)=0

I got the equations for displacement. They are:
For 0<t<1
t2/2 + 3t + C
For 1<t<2
5t - t2/2 + C

I cannot figure out how to evaluate that constant and plot that on a graph.
Hi southernbelle!

x(0)=0, so t2/2 + 3t + C has to be 0 when t = 0, so C = … ?
Also, my teacher mentioned finding the area under the original curve and plotting that. The area = 3.5but that's not a point to plot. What do I dO?
ah … your 3.5 is just the area for t = 1 …

your teacher meant the area A(t) up to time t for any t

plot A(t) against t, and that's the displacement.

HallsofIvy
Science Advisor
Homework Helper
You have
For 0<t<1
x(t)= t2/2 + 3t + C
For 1<t<2
x(t)=5t - t2/2 + C
and x(0)= 0.

Be careful- the two "C"s are necessarily the same.

Use x(0)= 0 to find C in the first equation. Then use the fact that the two equations must give the same result at x= 1 to find C in the second equation.

Okay, so

I evaluated the constants.
For the first equation:
C = 0
For the second equation
C = -1

But how do I plot those? Would I use the coordinates (0,0) and (1, -1) ?

I am thinking that the Constant is where you start on the y-axis and then you use the slope to go from there.

But the equation is not written in slope intercept form.
? :(

minger
Science Advisor
Well it's not slope intercept form because it's not a simple linear equation. Graphing these is quite easy. Time is your independant variable, it depends on nothing, so it's your x-axis. The velocity/disp/accel are dependent on time x = f(t), so it's your y-axis. Just start at t=0, plug it into your equation and put a point, then go to 0.1, or whatever you choose, and calculate x. Rinse and repeat until you get to time = 1.0 seconds, then switch to the other equation.