Acceleration in Rindler coordinates

Click For Summary
SUMMARY

The discussion centers on the concept of constant acceleration in Rindler coordinates, specifically addressing the relationship between inertial coordinates (X,T) and Rindler transformations (x,t). The equations x=Xcosh(aTc) and t=Xc sinh(aTc) describe a uniformly accelerated frame moving along hyperbolic paths. The key takeaway is that proper acceleration, measured by an accelerometer, is invariant and corresponds to the norm of the 4-acceleration, confirming that the acceleration remains constant regardless of the frame of reference.

PREREQUISITES
  • Understanding of Rindler coordinates and transformations
  • Familiarity with concepts of proper acceleration and 4-acceleration
  • Knowledge of special relativity (SR) principles
  • Basic grasp of hyperbolic functions and their applications in physics
NEXT STEPS
  • Study the derivation of Rindler transformations in detail
  • Explore the concept of 4-acceleration in special relativity
  • Investigate the implications of constant acceleration on particle motion
  • Learn about the relationship between hyperbolic functions and spacetime diagrams
USEFUL FOR

This discussion is beneficial for physicists, students of relativity, and anyone interested in the mathematical foundations of acceleration in non-inertial frames.

Ali.Sadeghi
Messages
1
Reaction score
0
[Mentors note: this thread was split off from an older discussion of Rindler coordinates]

Can somebody help me understand why acceleration along the hyperbola is constant?
To be more precise: assume (X,T) is the inertial coordinates and (x,t) the corresponding Rindler transformations.

x=Xcosh(aTc )
t=Xc sinh(aTc )

A uniformly accelerated frame moves along the curves with constant x.

What do we men by fixed acceleration here? is it second derivative of x relative to t? if x is constant then its first and second derivatives are of course zero. The second derivative of X relative to T cannot be a constant either, because that would imply a parabolic and not hyperbolic path with no limit on speed of light.

The only possibility that I can see is second derivative of X relative to t. is that indeed what we mean by constant acceleration along the hyperbola? And if so how can one prove that it is constant (equal to a)?
 
Last edited by a moderator:
Physics news on Phys.org
Ali.Sadeghi said:
Can somebody help me understand why acceleration along the hyperbola is constant?
To be more precise: assume (X,T) is the inertial coordinates and (x,t) the corresponding Rindler transformations.

x=Xcosh(aTc )
t=Xc sinh(aTc )

A uniformly accelerated frame moves along the curves with constant x.

What do we men by fixed acceleration here? is it second derivative of x relative to t? if x is constant then its first and second derivatives are of course zero. The second derivative of X relative to T cannot be a constant either, because that would imply a parabolic and not hyperbolic path with no limit on speed of light.

The only possibility that I can see is second derivative of X relative to t. is that indeed what we mean by constant acceleration along the hyperbola? And if so how can one prove that it is constant (equal to a)?
By acceleration is meant what is measured by an accelerometer. In SR, this is predicted (as a magnitude) to be the norm of the 4-acceleration, which is the derivative by proper time of the of the 4-velocity. As such, it (proper acceleration) is an invariant scalar that would be computed to be the same in any coordinates used to describe the world line (consistent with the idea that change coordinates used to describe the world do not change readings on a given measuring device).
 
Consider an inertial frame in which the spaceship is at momentarily at rest. This would be the inertial frame of a dropped object on the spaceship, because the spaceship and the object are moving at the same speed at the moment that the object is released (and we'll take that moment to be time zero in that frame).

In this inertial frame, the the velocity of the ship at time zero is zero, but the first derivative of that velocity is not. That first derivative, evaluated at t=0, is the Rindler acceleration ##a##. It is easy enough to show that it is a constant, meaning that you'll come up with the same value no matter what the speed of the ship is at the moment that the object is dropped.

All of this is equivalent to what PAllen said above, of course.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K