Acceleration of 4kg Object w/ Force at 37 Degrees

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SUMMARY

The acceleration of a 4 kg object subjected to forces of 50N and 100N at an angle of 37 degrees can be calculated using Newton's second law, F=ma. For a 50N force, the acceleration is confirmed to be 10 m/s² in the x-direction. However, when applying a 100N force, the net upward force results in an acceleration of 20.6 m/s² in the upward direction. This calculation incorporates both the horizontal and vertical components of the applied force, utilizing the sine and cosine values for the angle provided.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Basic trigonometry (sine and cosine functions)
  • Knowledge of vector components in force analysis
  • Ability to perform calculations involving mass and acceleration
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  • Study vector decomposition of forces in physics
  • Learn about the effects of angle on force application
  • Explore advanced applications of Newton's laws in dynamics
  • Investigate real-world examples of force and acceleration calculations
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of force and acceleration problems.

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Homework Statement


Find the acceleration of the object in the figure with mass 4 kg when it's applied a force of a)50N b)100N and which makes an angle of 37degrees.(sin 37=0.6,cos 37=0.8)
[PLAIN]http://img97.imageshack.us/img97/5863/forceg.png

Homework Equations


F=ma

The Attempt at a Solution


I have tried to take first Fx=ma for 50N which goes in the direction of x-axis I got 10m/s^2 which is correct but when i try with 100N with Fy=ma I don't get the correct answer.Or with Fx=ma
could you please help me?
 
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When the 100N force is applied, note that there is a net upwards force on the block and hence the block has an upward acceleration. Factor that in and you should get the correct answer.
 
When it applied 100N it should be 20.6m/s^2 upwards direction.
 

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