(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The figure below shows an initially stationary block of mass m on a floor. A force of magnitude F=0.540mg is then applied at upward angle θ = 21°.

(a) What is the magnitude of the acceleration of the block across the floor if (a) s = 0.600 and k = 0.500?

(b) What is the magnitude of the acceleration of the block across the floor if s = 0.400 and k = 0.300?

2. Relevant equations

F=ma and F=s(N) or F=k(N)

3. The attempt at a solution

Well i drew a Free Body Diagram and found the forces in the x and y direction:

x: F(s)-Fcos(21)=0

y: mg-Fsin(21)-N=0

Then i solved for F(s)=Fcos(21)=0.54mg(cos(21))=4.94m

then i used F=s(N) to solve for N

N=8.233m

Then i set F=ma and F=s(N) equal and solved for a

a=8.233(.500)=4.11

I repeated the same steps for B...but the answers are not correct. Any help at all will be appreciated!

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# Homework Help: Acceleration of a block on the floor

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