Acceleration of a Cart Pulled by Different Forces

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SUMMARY

The acceleration of a 0.50 kg cart on a level track, pulled by a 0.25 kg mass over a pulley, is calculated to be 5 m/s², assuming no friction. The tension in the string, created by the hanging mass, is 2.5 N, which is equivalent to the force exerted by a student pulling the string with the same force. Therefore, the acceleration remains unchanged at 5 m/s² regardless of whether the force is applied by the mass or by a student pulling with 2.5 N.

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please help :) force question

Homework Statement



Use g=10 N/kg for this problem.
A 0.50 kg cart is on a level track. A horizontal string is pulling the cart. The string goes over a pulley and there is a 0.25 kg mass hanging at the other end.

a) What is the acceleration of the cart, if there is no friction>

b) Would the acceleration be different if there were a student pulling the string with a force of 2.5 N, rather than the 0.25 kg mass doing the pulling?

Homework Equations



T+(-mg)=ma

The Attempt at a Solution



for part B, i said it wouldn't matter because ultimately, 2.5 N=0.25 kg in this case because 2.5= 10*(m).
 
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The 0.25 kg mass hanging from the string pulley creates a tension T = m*g

T = 0.25 * 10 = 2.5N

The tension is the same all the way to the cart. As per the problem the cart has no friction.
So the cart weighing 0.5 kg is being moved by a force T = 2.5N

Acceleration is 2.5N/0.5 = 5m/sec^2

If a student pulled instead of the 0.25 kg mass, it would generate 2.5N force and the acceleration would be same.
 

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