Acceleration of a cart being pulled by a falling mass

Click For Summary
SUMMARY

The discussion focuses on the dynamics of a cart being accelerated by a falling mass via a pulley system. The cart has a constant mass of 1 kg, while the falling mass varies across four trials (0.1 kg to 0.4 kg). The participant graphed the acceleration of the cart against the net pulling force, calculated using the equation F = m * g, where g is 9.81 m/s². The participant clarified that the total mass of the system must be considered for accurate calculations, leading to a linear relationship in the graph when plotted correctly.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with pulley systems and their mechanics
  • Knowledge of basic physics equations, including F = m * a
  • Ability to perform experimental measurements and data plotting
NEXT STEPS
  • Explore the concept of net force in multi-body systems
  • Learn about graphing techniques for physics experiments
  • Study the effects of varying mass on acceleration in pulley systems
  • Investigate the use of spark timers for measuring acceleration
USEFUL FOR

Students in physics courses, educators teaching mechanics, and anyone interested in experimental physics involving motion and forces.

jumbogala
Messages
414
Reaction score
4

Homework Statement


I'm doing a lab and getting very confused.

A cart is on a table. It is attached to a string which goes over a pulley. The pulley is on the edge of the table.

On the end of the string there is a mass. When the mass falls straight down, it pulls on the string and makes the cart accelerate too.

Homework Equations


Mass of the cart = 1 kg (constant)
Trial 1: mass falling down: 0.1 kg & mass added to cart: 0.4 kg
Trial 2: mass falling down: 0.2 kg & mass added to cart: 0.3 kg
Trial 3: mass falling down: 0.3 kg & mass added to cart: 0.2 kg
Trial 4: mass falling down: 0.4 kg & mass added to cart: 0.1 kg

The Attempt at a Solution


I am supposed to graph the acceleration of the cart vs. the pulling force. However, I am not sure what this graph should look like.

For trial 1, the pulling force would be (0.1 kg)*(9.81 m/s2)=0.981 N, right? And the theoretical acceleration would be 0.981 N/(0.4 kg+1kg) = 1.962 m/s2.

However, if I graph a vs. F, I don't get a straight line, because the mass of the moving object is always changing. Is this right? In the book they make a big deal about the total mass of the system being constant, so I'm wondering if that has something to do with it.
 
Physics news on Phys.org
The big deal is not for nothing: it is not only the cart that accelerates, the pulling mass doesn't stay in the same place either! In fact it accelerates just as fast as the cart. And that requires some force too!
[edit] but I see you correctly take that into consideration.
 
  • Like
Likes   Reactions: 1 person
Out of curiosity: what is being measured and how do you process the measurements to get a plot? Can you show the plot(s) you have so far ?
 
Thank you! I'm not sure what I was thinking. It makes much more sense to divide by the total mass. I did take it into consideration but then forgot to include in in my calculation.

Basically I just found the net force for each trial based on the weight of the falling mass. Then, I calculated the acceleration of the cart using a spark timer. I put the net force on the y-axis and the acceleration on the x, which gives a slope of m (total mass).

Unfortunately I did the plot by hand and I don't have a scanner handy, but it seems to be working out now. Thanks a ton for your help, much appreciated!
 
More than welcome. Good luck further on!
 

Similar threads

Replies
14
Views
3K
Replies
44
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
9K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
8
Views
6K
Replies
4
Views
1K