Acceleration of a sliding mass with a sliding mass on top of it?

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SUMMARY

The discussion centers on the dynamics of two objects, A and B, where object A accelerates on a rough horizontal surface while object B slides on top of it. The key point is that when applying Newton's second law (Fnet = ma) to object A, only the mass of object A should be considered, despite the presence of object B. The friction forces acting on object A include f1, opposing its motion, and f2, aiding its motion due to object B. Thus, the correct force equation for object A is Fx = f2 - f1 = (mass of A only) * a.

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Blkmage
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Say we have a rectangular object A accelerating with some acceleration a across a rough horizontal surface. Object B starts with velocity v on the top left corner and slides across the top of A subject to a friction force.

Now if we consider object A by itself, it is subject to a friction force between itself and the surface opposing the direction of motion (call it f1), and a friction force between itself and object B in the direction of motion (call it f2), correct?

So since we are considering object A by itself, is the force equation in the horizontal direction

Fx = f2 - f1 = (mass of A only)*a

or

Fx = f2 - f1 = (mass of A+B)*a

My intuition tells me it should be the second one since the object B is exerting a downward force on A, which contributes to the weight and therefore the mass. Is this right?
 
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hello,

when applying Fnet = ma to object A, you must use only the mass of object A. the increase in the friction force (and the introduction of a second friction force) accounts for the presence of object B.

hope this helps
 

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