Acceleration of an object given forces

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Zack K
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Homework Statement


An 85 kg tobbogan that was originally accelerating at 3.0 m/s2 on frictionless snow hits a bare patch of concrete that exerts a force of friction on the sled of 180 N, what will the new acceleration be?

Homework Equations


F=ma

The Attempt at a Solution


Ok so this was originally a 2 part question but I merged it into one. I already calculated the applied force of the tobbogan on frictionless snow which is 255 N east. Now I have to find its acceleration when it hits the concrete. So I got the Fnet by subtracting the applied force by the force of friction. 255-180= 75 N east. So now I do a=F/m. So the acceleration by my understanding should be 75/85 which is 0.88 m/s2. But the answer sheet says that it is 0.94 m/s2.
 
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Zack K said:
225-180= 75 N
=45N not that it helps.

I suggest you post the question word for word in case there is something you missed when you merged it into one question.
 
CWatters asked for the original unmerged question. You seem to have just reposted your merged version.
In particular, if any of the input numbers you quote in the merged version are actually results calculated for the first part of the question, they may contain rounding errors that become significant in the second stage.
 
CWatters said:
=45N not that it helps.

I suggest you post the question word for word in case there is something you missed when you merged it into one question.
225
haruspex said:
CWatters asked for the original unmerged question. You seem to have just reposted your merged version.
In particular, if any of the input numbers you quote in the merged version are actually results calculated for the first part of the question, they may contain rounding errors that become significant in the second stage.
Sorry I accidentally posted that and am trying to delete it. I don't know how to delete. Also the answer I got was a whole number. No rounding was required
 
Thanks guys for the help. I'm assuming that the answer key had a typo.