Acceleration of Car: How to Find the Equation for Acceleration | Help Needed

  • Thread starter Thread starter flasheddread
  • Start date Start date
  • Tags Tags
    Acceleration Car
Click For Summary

Discussion Overview

The discussion revolves around finding an equation for the acceleration of a car, considering its mass and the moment of inertia of its tires. Participants explore the relationship between torque, friction, and acceleration, addressing both theoretical and practical aspects of the problem.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to begin solving for acceleration, initially proposing an equation that seems incorrect.
  • Another participant clarifies that the only external force acting on the car is friction and introduces the concept of rolling constraint, stating that acceleration relates to angular acceleration.
  • A participant attempts to relate torque and acceleration but questions their understanding of how moment of inertia affects acceleration.
  • There is a suggestion to express everything in terms of torque supplied by the engine, emphasizing the need to consider the unknown friction force.
  • A participant revises their approach, proposing a new equation for acceleration based on torque and moment of inertia, but another participant points out that they have not accounted for the mass of the car or the friction force.
  • Participants discuss the relationship between torque, friction, and acceleration, with one participant suggesting that friction can be expressed as mass times acceleration.
  • There is a mention of an effective "rolling mass" concept that allows for simplifying the analysis by treating the moment of inertia as an additional mass term.
  • One participant questions whether torque should also be divided by the radius, leading to a correction from another participant.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the final equation for acceleration, as there are multiple viewpoints and ongoing clarifications regarding the roles of torque, friction, and moment of inertia.

Contextual Notes

There are unresolved assumptions regarding the nature of the friction force and its relationship to the car's acceleration. The discussion also reflects varying levels of understanding about the application of torque and moment of inertia in this context.

flasheddread
Messages
6
Reaction score
0

Homework Statement


I have a car with a mass (m) and tires having moment of inertia (I). I need to find an equation for the acceleration of the car from what is given. thanks in advance for the help.


Homework Equations


Not sure what all is relevant here but, M=I[itex]\alpha[/itex] F=ma


The Attempt at a Solution


I really have no idea how to even begin this. My attempt got me a=I[itex]\alpha[/itex]/m and I am pretty sure this isn't correct
 
Physics news on Phys.org
welcome to pf!

hi flasheddread! welcome to pf! :smile:

(have an alpha: α :wink:)

the only external force on the car is the friction, F

(so the external torque is Fr)

you'll also need the rolling constraint, a = rα :wink:

(you'd better assume it's four-wheel drive … two-wheel drive gets rather complicated)​
 
:) thanks

I get that friction is the only external force here. I guess I'm just having trouble understanding how to get the acceleration for the car using the moment of inertia.

I start off by saying the Fr=Iα, which is the torque created by the tires that will move the car. Then i need to relate that to the acceleration of the car so i say Fr=ma?? Now this is where I think I'm messing up. I say that Iα=ma and rearranging that, I can say that a=Iα/m.

I know this is completely wrong, since having a bigger moment of inertia for the tires would mean the car would accelerate slower, and this equation proves the opposite. Or would this be correct because the acceleration is on determined by how much force is placed on the tires to rotate? Maybe I'm just thinking about this too hard, because it doesn't seem that difficult.

Any help please??
 
Last edited by a moderator:
Alrighty I think I might have it now!

The engine supplies a torque to the tires, which in turn gives them an angular acceleration.
τ=Iα
α=a/r

so, a= τr/I

This makes much more sense. I have no idea what I was thinking earlier. I'm pretty sure this is correct this time, :smile: and if not I might just drop out of college. :cry:
 
wait a mo! :rolleyes:

you haven't used either the mass of the car, or the friction force F

don't forget that there are two torques on the wheel (why do you keep saying "tires"? :redface:), the known applied torque τ from the engine and the unknown torque from the friction from the road (which you'll have to eliminate) :wink:
 
Oh wow, yea that's just what kind of day I was having yesterday. :frown: Sorry for being so difficult and thanks for sticking around for me.

Alright so about this friction force. Would we eliminate it by saying the friction force is equal to the mass times acceleration of the car? If so and I am doing this correctly we get.

τ-Fr=Iα, which then goes to τ-mar=Ia/r

And from here its just manipulating it to solve for a.
 
hi flasheddread! :wink:
flasheddread said:
Alright so about this friction force. Would we eliminate it by saying the friction force is equal to the mass times acceleration of the car?

yup, the https://www.physicsforums.com/library.php?do=view_item&itemid=39" on both axles), so F = ma :smile:
If so and I am doing this correctly we get.

τ-Fr=Iα, which then goes to τ-mar=Ia/r

And from here its just manipulating it to solve for a.

exactly :smile:

btw, note that if you fivide by r, you get τ = (m + I/r2)a,

so effectively we can ignore the friction if we pretend that the wheels have an extra "rolling mass" of I/r2 :wink:
 
Last edited by a moderator:
Wouldn't torque be divide by r as well?
 
  • #10
oops!

oops! :redface:

yes … τ/r = (m + I/r2)a :smile:
 
  • #11
Sweet, thanks so much for your help! I will keep rolling mass in memory; it sounds pretty useful. :smile:
 

Similar threads

  • · Replies 40 ·
2
Replies
40
Views
8K
  • · Replies 16 ·
Replies
16
Views
7K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K