- #1
songoku
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- Homework Statement
- A U-pipe having uniform cross sectional area is filled with water. The picture on the left is when the U-pipe is at rest and picture on the right is when the U-pipe is accelerated with acceleration ##a##. Find ##a## in terms of gravitational acceleration, ##g##
##a) \left(\frac{2h}{L}\right)g##
##b) \left(\frac{h}{L}\right)g##
##c) \left(\frac{h}{2L}\right)g##
##d) \left(\frac{h}{L}\right)^2 g##
##e) \left(\frac{2h}{L}\right)^2 g##
- Relevant Equations
- ΣF = m.a
P = F/A
P = ρ.g.h
I am thinking of using ΣF = m.a to find the acceleration but I don't know what causes the resultant force to the right. I thought it will be the difference in pressure on the left and right leg of the U-pipe (picture on the right), which is ΔP = ρ.g.h but the force (ΔP . A) won't be directed to the right (it will be downwards).
What approach should I use to solve this question? Thanks