A pedestrian is running at v=6m/s (continuously) to catch a bus that is leaving from 16m in front of him. The bus pulls away and accelerates (from rest) at 1m/s/s.
How far does the pedestrian have to run to catch the bus (if at all)?
acceleration bus= 1m/s/s
The Attempt at a Solution
How would i go about solving this one? Its easy to solve for there intersection, but i'm not sure how to incorporate the 16m head start by the bus into a equation.
i used: v1(delta-t)+0.5a(delta-t)^2=v(delta-t)
to find the distance at which they meet, but would the equation with the 16m be:
This way doesn't look right to me so im wondering how it should be incorporated.
So how can i incorporate the 16m head start by the bus into the equation?
delta distance=v1 (delta time)+0.5(acceleration)(delta time)^2
v1 (delta time)+0.5(acceleration)(delta time)^2=v(delta time)
Times cancel leaving v1 =0 so its gone