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Acceleration through PD, relativistic momentum

  1. Dec 17, 2011 #1
    When accelerating an electron through a PD of 10^3, that will give a momentum of 1 MeV/c right? Or is there something I'm not taking into account with relativity?

    Thanks :D
  2. jcsd
  3. Dec 17, 2011 #2

    Meir Achuz

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    You probably meant PD=10^6 volts. Then, the NR formula would give p-1 MeV.
    But the relativistic result is 1.4 MeV.
  4. Dec 17, 2011 #3
    Ah yes sorry I did, but how would I would out the relativistic result like you did?
  5. Dec 17, 2011 #4
    So I've used K=Vq, then K+m(c^2)=E to get the energy and I've got approximately the right answer, but when I divide by c to get units from MeV to MeV/c for momentum I'm of course not even in the same order of magnitude.
  6. Dec 17, 2011 #5
    Nevermind, I think I must have the right answer I was just thinking that /c had already happened.
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