Calculating Acceleration and Angle on a Frictionless Air Track

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The discussion focuses on calculating the acceleration and angle of a cart on a frictionless air track. Given that the cart travels 32.0 cm in 2.0 seconds, the acceleration can be determined using the formula d = (1/2) a t^2, leading to an acceleration of 8.0 m/s². The angle θ of the track can be calculated using the relationship a = g cos(θ), where g is the acceleration due to gravity (9.81 m/s²). The user successfully solved the problem with the provided guidance.

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Please help me with this question. I understand how to calculate the velocity from the given conditions but I don't know how to figure out the acceleration or the angle. Thanks!

A cart is released from rest at the top of a perfectly frictionless air track. After an elapsed time delta t = 2.0s, the cart has traveled delta x = 32.0 cm down the track. What is the cart's acceleration? What is the angle of theta of this track?
 
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The acceleration of the cart is the component of its weight parallel to the track divided by its mass so a = g \cos \theta. The distance it travels is

d = \frac {1}{2} a t^2

and you have enough information to find the acceleration and the angle.
 
I've figured out the problem with your help. Thank you!
 

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