Accuracy of Gravity: -9.8m/s/s +- _______m/s/s

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SUMMARY

The accuracy of gravity is defined as -9.8 m/s², but it is subject to variations based on geological and altitude factors. In laboratory experiments, the accuracy error for gravity can be treated as zero if external variables are controlled. When calculating force using the equation f=mg, the total accuracy error is derived from the mass's accuracy error and the gravity's accuracy, leading to the formula: total accuracy = (accuracy of m/m) + (accuracy of gravity/g). The value used for gravity in calculations should be -9.8 m/s².

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  • Understanding of basic physics concepts, specifically Newton's laws of motion.
  • Familiarity with the equation f=mg (force equals mass times gravity).
  • Knowledge of measurement accuracy and error propagation techniques.
  • Basic understanding of how geological and altitude factors affect gravitational measurements.
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StephenDoty
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I am working on a lab and I need to know the accuacy of gravity=-9.8m/s/s? So I need the +- blank after the -9.8m/s/s. -9.8m/s/s +- _________m/s/s

Thank you

Stephen Doty
 
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Is there an accuracy error for gravity? Or do you just use the other number's accuracy error as the error of accuracy when doing f=mg. So the m has an accuracy is +-.02g so when doing f=mg what do I do for the accuracy error of gravity in the equation: total accuracy error= accuracy error of m/m + accuracy error of gravity/g.
 
Just use the accuracy level of things you actually measure. g is not constant, it depends on geology and altitude among other things. But those aren't likely to be variables in your lab experiment.
 
So for the accuracy equation for the f=mg : total accuracy= (.00002kg)/0.2704kg + 0/(9.8m/s/s)

From the equation: total accuracy = accuracy of m/m + accuracy of gravity/g

And for f=mg do I use (-9.8m/s/s) or (9.8m/s/s)
 

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