Acidic strength of phenol with isotopic oxygen i.e O 18 and just phenol

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SUMMARY

The discussion centers on the acidic strength comparison between phenol and phenol with isotopic oxygen (O-18). It establishes that O-18, despite having the same number of protons as O-16, possesses two additional neutrons, affecting the zero point energy (ZPE) of the molecule. The lower ZPE of O-18 phenol leads to a different dissociation pathway and activation energy compared to O-16 phenol. The isotope effect is highlighted as a significant factor in determining the stability of the conjugate base and the complexity of predicting these differences.

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  • Understanding of acidic strength and conjugate bases
  • Familiarity with isotopes, specifically O-16 and O-18
  • Basic knowledge of quantum mechanics and zero point energy
  • Concept of kinetic isotope effects in chemical reactions
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  • Research the concept of zero point energy in quantum mechanics
  • Study the kinetic isotope effects and their implications in chemical reactions
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Chemists, particularly those specializing in physical chemistry, researchers studying isotope effects, and students seeking to understand the nuances of acidic strength in isotopic compounds.

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I have a doubt between the acidic strength of phenol with isotopic oxygen i.e O 18 and just phenol
 
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What kind of doubt do you have?
 
Acidic strength comparison between phenol and phenol with O18
 
I don't know how to compare between
 
O18 has 2 extra proton so conjugate base must be more stable than that in O??
 
O18 has the same number of protons as O16.
 
It has two extra neutrons
 
I searched it somewhere and they said something about zero point energy. But I dont understand what it is!!
 
Sat-P said:
I searched it somewhere and they said something about zero point energy. But I dont understand what it is!!
It’s an example of the isotope effect. This is a really complex topic, but a simplified explanation goes like this: the zero point energy of an oscillator decreases with increasing mass, so the O-18 phenol OH vibration will have a lower ZPE than O-16 H. In addition, the transition state ZPE to break the OH bond will be different. In general these two ZPEs don’t decrease by the same amount, so one dissociation pathway will have a lower activation energy than the other. Predicting the magnitude and sign of this difference can be very complicated, but the magnitude is generally proportional to the mass difference between the isotopes. So O-18/O-16 isotope effects will be quite a bit smaller than H/D isotope effects. This page has a pretty good explanation with pictures and examples:
https://chem.libretexts.org/Bookshe...l_Harmonic_Oscillator/Kinetic_Isotope_Effects
 

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