Activation energy of parallel reaction

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SUMMARY

The activation energy of a parallel reaction can be calculated using the Arrhenius equation: e = (e1k1 + e2k2) / (k1 + k2), where e1 and e2 are the activation energies, and k1 and k2 are the rate constants for two reactions. In the context of reactions A → B and A → C, the total activation energy required is expressed as e = e1*dB + e2*dC, where dB and dC represent the moles of products formed. The discussion confirms that this method for calculating overall activation energy is valid, despite acknowledging that temperature variations may influence the results.

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  • Understanding of the Arrhenius equation
  • Knowledge of reaction kinetics
  • Familiarity with rate laws
  • Basic concepts of chemical thermodynamics
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adi1998
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Well,I know that the activation energy of a parallel reaction can be determined by the arrhenius
equation as (e1k1+e2k2)/(k1+k2) where e1,k1 and e2,k2 are the activation energies and rate constants for the two reacations.now consider the reaction A》B,and A》C since at every instant the reacted amount of A(in moles) is the sum of amounts of B and C produced,assume that in time dA moles of A react.the energy of activation required will be e1*dB+e2*dC=e*dAwhere dB and dC moles of B and C are formed and the total energy of activation being e.Using the rate law definition now yields the same result.Is this proof also valid?I understand that these are all crude approximations(temperature changes may affect the result etc)
 
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adi1998 said:
Is this proof also valid?
Proof of what? What in particular are you trying to accomplish?
 
I am talking about the expression for the overall activation energy
,given by e=(e1k1+e2k2)/(k1+k2).
 

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