Paymemoney
- 175
- 0
Homework Statement
Draw the vector [tex]\vec{C} = \vec{A}+2\vec{B}[/tex]
Homework Equations
None
The Attempt at a Solution
This is what i have i don't know if it is correct
P.S
Adding Scalar Multiples of Vectors in a Graph
17 replies · 30K views · last reply
Draw the vector [tex]\vec{C} = \vec{A}+2\vec{B}[/tex]
None
This is what i have i don't know if it is correct
P.S
Discussion
Paymemoney
- 175
- 0
ok so is this what it should look like:
)
Paymemoney
- 175
- 0
how i do this without bending it? So is it only meant to go horizontally?
Paymemoney
- 175
- 0
so would this be correct.
does it matter where you place the vector, because when i placed it in the middle it was incorrect??
does it matter where you place the vector, because when i placed it in the middle it was incorrect??
Science Advisor
Homework Helper
- 25,837
- 258
Hi Paymemoney! 
(just got up :zzz: …)
Nooo …
I think I need to give you the answer:
(or the other way round, of course: place the "tail" of the first vector against the "head" of the second vector: it makes no difference)
So in this case, you draw A which is an arrow going 4 to the right, then you draw B which is an arrow going 2 to the left, and you draw that 2 starting at the end of the 4, so you end up with an everall vector of A + 2B being 2 to the right.
(this is just like adding vectors to make a triangle, except that in this case the triangle is flat
)
(just got up :zzz: …)
Paymemoney said:
Nooo …
I think I need to give you the answer:
To add two vectors, you must place the "tail" of the second vector against the "head" of the first vector: the sum is then the vector to that point (from where you started).
(or the other way round, of course: place the "tail" of the first vector against the "head" of the second vector: it makes no difference)
So in this case, you draw A which is an arrow going 4 to the right, then you draw B which is an arrow going 2 to the left, and you draw that 2 starting at the end of the 4, so you end up with an everall vector of A + 2B being 2 to the right.
(this is just like adding vectors to make a triangle, except that in this case the triangle is flat
)
Paymemoney
- 175
- 0
ok, this is what i got from your explanation, so just to make sure i have interpreted your explanation correctly here it is again(hopefully correct -_-).tiny-tim said:
tiny-tim said:(this is just like adding vectors to make a triangle, except that in this case the triangle is flat
yeh, I'm used to looking at the full triangle.
Science Advisor
Homework Helper
- 25,837
- 258
Paymemoney said:
I don't understand what you've done here.
Start on the axis, draw a blue line for A, then from the end of that draw a red line for 2B. Now draw a green line from the axis to the end of the red line (as if you were completing a triangle).
Paymemoney
- 175
- 0
ok here it is
why don't you draw it for me coz i don't think I'm getting anyway.
why don't you draw it for me coz i don't think I'm getting anyway.
Paymemoney
- 175
- 0
after thinking more about it, i have come to a conclusion that this may be the answer but I'm not sure:
Mentor
- 38,158
- 10,768
No, not right. A is 4 units long and points to the right. B is 1 unit long and points to the left. 2B is 2 units long and points to the left.
For the sum A + 2B, start at 0, go 4 units to the right. Now tack 2B on. Where do you end up? The vector from 0 to where you ended up is A + 2B.
Since all vectors involved here are horizontal, the sum will be a horizontal vector: one that points either to the right or to the left.
For the sum A + 2B, start at 0, go 4 units to the right. Now tack 2B on. Where do you end up? The vector from 0 to where you ended up is A + 2B.
Since all vectors involved here are horizontal, the sum will be a horizontal vector: one that points either to the right or to the left.
Paymemoney
- 175
- 0
What do you mean by "Now tack 2B on"?
Paymemoney
- 175
- 0
ok, i had another go at it, and this is what i got:
Last edited:
Mentor
- 38,158
- 10,768
We're 16 posts into this thread, and you still aren't getting it. Why do you have two diagrams? Are we supposed to pick one?
In the right diagram, the resultant (black) vector starts at the right place, but it's too short. In the left diagram, the resultant vector is the right length, but it starts at the wrong place.
In the right diagram, the resultant (black) vector starts at the right place, but it's too short. In the left diagram, the resultant vector is the right length, but it starts at the wrong place.
Paymemoney
- 175
- 0
well i finally got the answer =___=, yeh it took me awhile because i didn't read the answer you gave me correctly. thanks for the help anyways.