Adiabatic Process and Heat Absorption

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SUMMARY

An adiabatic process, characterized by no heat exchange, was analyzed for 15 moles of an ideal gas with an initial temperature of 320 K and an initial volume of 0.80 m³, which was compressed to a final volume of 0.40 m³. The adiabatic constant for the gas is 1.44. The heat absorbed by the gas is definitively zero, confirming that in an adiabatic process, there is no heat gained or lost, as stated by the equation Q=0.

PREREQUISITES
  • Understanding of adiabatic processes in thermodynamics
  • Familiarity with ideal gas laws
  • Knowledge of thermodynamic equations, specifically Q=0
  • Basic concepts of heat transfer in isolated systems
NEXT STEPS
  • Study the principles of thermodynamics, focusing on adiabatic processes
  • Learn about the ideal gas law and its applications
  • Explore the implications of the first law of thermodynamics in isolated systems
  • Investigate real-world applications of adiabatic processes in engineering
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Students studying thermodynamics, physics enthusiasts, and professionals in engineering fields focusing on heat transfer and energy systems.

jimbo71
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Homework Statement


An adiabatic process is performed on 15 moles of an ideal gas. the initial temperature is 320 K and the initial volume is 0.80m^3. the final volume is 0.40m^3. the adiabatic constant for the gas is 1.44
the heat absorbed by the gas in kJ is closest to
a. 0
b.+54
c.-14
d.-32
e.+14




Homework Equations


Q=0



The Attempt at a Solution


I think the heat absorbed by the gas is zero. I think this is a trick question because an adiabatic process involves no heat gained or lost. However, maybe I just misunderstand what consitutes an adiabatic process.
 
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You are right. An adiabatic process occures in the isolated system.
 

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