So I've been trying to figure this out. The question is:(adsbygoogle = window.adsbygoogle || []).push({});

If the limit x->infinity of Xn=Xo

Show that, by definition, limit x->infinity sqrt(Xn)=sqrt(Xo)

I'm pretty sure I need to use the epsilon definition.

I worked on it with someone else and we think that what we have to show is the this:

Want to show:

For all e>0 there is an N>0 s.t. for all n>N, |sqrt(Xn) - sqrt(Xo)|<e

I just don't know how to show this.

Thanks!

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# Homework Help: Advanced Calc. Continuity problem

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