Advice required on Boolean algebra question

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Discussion Overview

The discussion revolves around the simplification of a Boolean expression. Participants explore methods for simplification, including algebraic approaches and the use of Karnaugh maps, while discussing the validity of certain terms in the expression.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a Boolean expression and claims to have simplified it to ~AB + ~A~C + ~AD + ~C~B, while suggesting that it can be further simplified to ~AB + ~AD + ~C~B.
  • Another participant questions whether the simplification needs to be done algebraically or if a Karnaugh map can be used instead.
  • A participant expresses unfamiliarity with Karnaugh maps but indicates a willingness to learn about them.
  • A later reply confirms that using a Karnaugh map leads to the same final three terms mentioned earlier.
  • Another participant expresses satisfaction in finding the expected terms and resolving an additional problem.

Areas of Agreement / Disagreement

Participants generally agree on the final terms of the simplification, but there is no consensus on the necessity of algebraic proof versus the use of a Karnaugh map.

Contextual Notes

Some participants rely on truth tables and Karnaugh maps, while others focus on algebraic methods, indicating a variety of approaches to the problem without resolving which is superior.

Steve Collins
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I have been asked to simplify this Boolean expression:

~A~B~C~D + ~A~B~CD + ~A~BCD + ~AB~C~D + ~AB~CD + ~ABC~D + ~ABCD + A~B~C~D + A~B~CD

I have simplified it down to:

~AB + ~A~C + ~AD + ~C~B

But I know that the simplification goes further to:

~AB + ~AD + ~C~B

I've looked at the truth table and seen that ~A~C is indeed superfluous, but I am unsure of how to prove this algebraically.
 
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Steve Collins said:
I have been asked to simplify this Boolean expression:

~A~B~C~D + ~A~B~CD + ~A~BCD + ~AB~C~D + ~AB~CD + ~ABC~D + ~ABCD + A~B~C~D + A~B~CD

I have simplified it down to:

~AB + ~A~C + ~AD + ~C~B

But I know that the simplification goes further to:

~AB + ~AD + ~C~B

I've looked at the truth table and seen that ~A~C is indeed superfluous, but I am unsure of how to prove this algebraically.

Can you use a Karnaugh map, or do you need to do it algebraically?
 
It doesn't need to be done algebraically, I just thought that was the way to do it.
I've heard of a Karnaugh map before, but have no idea what it is or does. I will look it up now.

Cheers

Steve
 
Steve Collins said:
It doesn't need to be done algebraically, I just thought that was the way to do it.
I've heard of a Karnaugh map before, but have no idea what it is or does. I will look it up now.

Cheers

Steve

Great! Yeah, using a K-map I got the final 3 terms that you listed.
 
Fantastic! I also found the 3 terms I was expecting and also solved another problem that was giving me some trouble.

Thanks berkeman.
 

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