I have been asked to simplify this Boolean expression:(adsbygoogle = window.adsbygoogle || []).push({});

~A~B~C~D + ~A~B~CD + ~A~BCD + ~AB~C~D + ~AB~CD + ~ABC~D + ~ABCD + A~B~C~D + A~B~CD

I have simplified it down to:

~AB + ~A~C + ~AD + ~C~B

But I know that the simplification goes further to:

~AB + ~AD + ~C~B

I've looked at the truth table and seen that ~A~C is indeed superfluous, but I am unsure of how to prove this algebraically.

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# Homework Help: Advice required on Boolean algebra question

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