1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How to simplify this boolean algebra (logic)

  1. Oct 29, 2012 #1
    This is related to logic circuits.
    How do I simplify this boolean algebra(logic) into its simplest expression?

    h = (abc + abd + acd + bcd)’

    My first attempt would be to change it into product-of-sum.
    h = (abc)'(abd)'(acd)'(bcd)'

    and then what next?
  2. jcsd
  3. Oct 29, 2012 #2
    h = (abc)'(abd)'(acd)'(bcd)'

    = (a'+b'+c')(a'+b'+d')(a'+c'+d')(b'+c'+d')

    = (a'+b'+c'+d)(a'+b'+c'+d')(a'+b'+c+d')(a'+b'+c'+d')(a'+b+c'+d')(a'+b'+c'+d')(a+b'+c'+d') (a'+b'+c'+d')


    I hope it is correct..
  4. Oct 29, 2012 #3
    Could you explain to me how you add the new terms into the expression?
  5. Oct 29, 2012 #4
    Let's assume we have :

    F = A'+AB

    = A'(B+B') + AB # B+B'= 1, will not affect the equation.

    = A'B + (A'B' + AB) # Cancel each other.

    = A'B

    By the same way :)
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: How to simplify this boolean algebra (logic)
  1. Simplify boolean algebra (Replies: 10)